Question: Per this article, what iPhone version will be able to reach to the moon?
Assuming:
Increase in icons is quadratic over time.
Each iPhone version requires an extra 8.6mm in height to hold the extra icons.
The distance to the moon is ~240,000 miles.
The length of the iPhone 1 is negligible.
Step One: Regress the data from the article to get the equation "y = 3.25x^2 - 27.65x + 76.95", where y = # of icons and x = iPhone version number.
Step Two: Convert equation to mm. 8.6mm increase for every 5 icon capacity (difference between iPhone 4 and 5) => multiply our equation by 8.6mm/5 icons => new equation is "y = 5.59x^2 - 47.558x + 132.354", where y = mm.
Step Three: Solve for x when y = 386,242,560,000mm (240,000 miles in mm).
*Answer: The iPhone 262,864 will be able to reach to the moon, opening up a key market for mobile users in the year 330,592 AD. It will debut with a little under 225 billion apps, too.
Assuming: Increase in icons is quadratic over time. Each iPhone version requires an extra 8.6mm in height to hold the extra icons. The distance to the moon is ~240,000 miles. The length of the iPhone 1 is negligible.
Step One: Regress the data from the article to get the equation "y = 3.25x^2 - 27.65x + 76.95", where y = # of icons and x = iPhone version number.
Step Two: Convert equation to mm. 8.6mm increase for every 5 icon capacity (difference between iPhone 4 and 5) => multiply our equation by 8.6mm/5 icons => new equation is "y = 5.59x^2 - 47.558x + 132.354", where y = mm.
Step Three: Solve for x when y = 386,242,560,000mm (240,000 miles in mm).
*Answer: The iPhone 262,864 will be able to reach to the moon, opening up a key market for mobile users in the year 330,592 AD. It will debut with a little under 225 billion apps, too.